A shopkeeper sells his milk at cost price but he add some water and earn 16(2/3)% profit. Find the ratio of milk and water

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Solution

Let he has to make milk to water ratio $1 : x$ to earn $\frac{50}{3}$ % profit
Let cost price of milk be $C$ /L
Then According to question $C \times$ ( $x + 1$ ) $= C \times \frac{7}{6}$
Solving we get $x = \frac{1}{6}$
So milk to water ratio = $6 : 1$

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A shopkeeper sells his milk at cost price but he add some water and earn 16(2/3)% profit. Find the ratio of milk and water

Let he has to make milk to water ratio 1:x to earn 503% profitLet cost price of milk be C/LThen According to question C× (x+1) =C×76Solving we get x=16So milk to water ratio = 6:1

Let he has to make milk to water ratio $1 : x$ to earn $\frac{50}{3}$ % profit
Let cost price of milk be $C$ /L
Then According to question $C \times$ ( $x + 1$ ) $= C \times \frac{7}{6}$
Solving we get $x = \frac{1}{6}$
So milk to water ratio = $6 : 1$