A shopkeeper sells milk which contains 5% water. What quantity of pure milk should be added to 2 litres of milk (containing 5% water) so that proportions of water become 4%?

1 litre

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2 litres

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0.5 litre

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0.75 litre

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None of these

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Solution

The correct option is C 0.5 litre

$∴ \frac{95}{100} + 2 + x = \frac{96}{100} (2 + x)$
or, 190+100x =192+96x or, 4x =2
or, x = 0.5 litres

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A shopkeeper sells milk which contains 5% water. What quantity of pure milk should be added to 2 litres of milk (containing 5% water) so that proportions of water become 4%?

The correct option is C 0.5 litre ∴95100+2+x=96100(2+x) or, 190+100x =192+96x or, 4x =2 or, x = 0.5 litres

The correct option is C 0.5 litre

$∴ \frac{95}{100} + 2 + x = \frac{96}{100} (2 + x)$
or, 190+100x =192+96x or, 4x =2
or, x = 0.5 litres