A short bar magnet is moved with constant velocity along the axis of a short coil. The magnet enters into the coil and then leaves it. The variation of induced emf (ε) with time (t) is best represented as
A
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B
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C
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D
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Solution
The correct option is B ⇒As per Lenz's law the emf will be induced such that, induced current's direction will produce a magnetic field (B), which opposes the (B) due to bar magnet.
∴In both cases induced emf will be of opposite sign,since flux through coil (ϕ↑) when magnet approaches it and (ϕ↓) when bar magnet goes past the coil. ⇒(b) option is correct, because it shows change in sign of emf.