wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A short bar magnet is placed in the magnetic meridian of the earth with the north pole pointing north. Neutral points are found at a distance of 30 cm from the magnet on the east - west line, drawn through the middle point of the magnet. The magnetic moment of the magnet in (Am2) is close to
(Given μ04π=107 in SI units and BH = Horizontal component of earth's magnetic field = 3.6×105 T)

A
4.9
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B

14.6
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
32.4
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
9.7
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D 9.7

As we know that magnetic field along the equatorial axis of the short bar magnet of magnetic moment M is given by

Bmagnet=μ04πMr3

At the neutral point,

Bmagnet=BH

μ04πMr3=3.6×105

M=3.6×105×(0.3)3107

M=9.72 Am2

<!--td {border: 1px solid #ccc;}br {mso-data-placement:same-cell;}--> Hence, (D) is the correct answer.

flag
Suggest Corrections
thumbs-up
1
similar_icon
Similar questions
View More
Join BYJU'S Learning Program
Join BYJU'S Learning Program
CrossIcon