A short bar magnet of magnetic moment 0.4JT−1 is placed in a uniform magnetic field of 0.16T. The magnet is in stable equilibrium. Then the potential energy is,
A
−0.64J
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B
Zero
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C
−0.082J
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D
−0.064J
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Solution
The correct option is D
−0.064J
Given M=0.4JT−1,B=0.16T
Stable equilibrium means θ between −→M & →B=0∘
So Potential energy U=−−→M.→B=−MBcos0∘U=−MBU=−0.4×0.16=−0.064J