A short bar magnet placed in a horizontal plane has its axis aligned along the magnetic north-south direction. Null points are found on the axis of the magnet at 14 cm from the centre of the magnet. The earth’s magnetic field at the place is 0.36 G and the angle of dip is zero. What is the total magnetic field on the normal bisector of the magnet at the same distance as the null point (i.e., 14 cm) from the centre of the magnet? (At null points, field due to a magnet is equal and opposite to the horizontal component of earth’s magnetic field.)
Given, Earth’s magnetic field, H=0.36 G
Distance of null point on the axis of magnet, r=14 cm=0.14 m
The magnetic field at distance r from the centre of the magnet on the axis of the magnet, B1=μ04π(2mr3)
Here, μ0=permeability of free space =4π×10−7 Tm/A