A short bar magnet produces magnetic fields of equal induction at two points on the axial line and the other on the equatorial line. Then the ratio of the distance is

1 : 2^{1 / 3}

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1 / 2

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2^{1 / 3} : 2

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2^{1 / 3} : 1

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Solution

The correct option is D $2^{1 / 3} : 1$
$B_{a x i a l} = \frac{2 μ_{0} m}{4 π d_{1}^{3}}$
$B_{e q} = \frac{μ_{0} m}{4 π d_{2}^{3}}$
$B_{a x i a l} = B_{e q}$
$\frac{2 μ_{0} m}{4 π d_{1}^{3}} = \frac{μ_{0} m}{4 π d_{2}^{3}}$
$(\frac{d_{1}}{d_{2}})^{3} = 2$
$\frac{d_{1}}{d_{2}} = 2^{1 / 3}$

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A short bar magnet produces magnetic fields of equal induction at two points on the axial line and the other on the equatorial line. Then the ratio of the distance is

The correct option is D 21/3:1Baxial=2μ0m4πd31Beq=μ0m4πd32Baxial=Beq2μ0m4πd31=μ0m4πd32(d1d2)3=2d1d2=21/3

The correct option is D $2^{1 / 3} : 1$
$B_{a x i a l} = \frac{2 μ_{0} m}{4 π d_{1}^{3}}$
$B_{e q} = \frac{μ_{0} m}{4 π d_{2}^{3}}$
$B_{a x i a l} = B_{e q}$
$\frac{2 μ_{0} m}{4 π d_{1}^{3}} = \frac{μ_{0} m}{4 π d_{2}^{3}}$
$(\frac{d_{1}}{d_{2}})^{3} = 2$
$\frac{d_{1}}{d_{2}} = 2^{1 / 3}$