A short bar magnet produces magnetic fields of equal induction at two points one on the axial line and the other on the equatorial line. The ratio of their distances is

2:1

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^{1 / 2}

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^{1 / 3}

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^{1 / 4}

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Solution

The correct option is A 2 $^{1 / 3}$ :1
$B o x i a l = \frac{2 μ_{0} m}{4 π d_{1}^{3}}$
$B (e w) = \frac{μ_{0} m}{4 π d_{2}^{3}}$
$B a x i a l = B e q$
$\frac{2 μ_{0} n}{4 π d_{1}^{3}} = \frac{μ_{0} m}{4 π d_{2}^{3}}$
$(\frac{d_{1}}{d_{2}})^{3} = 2$
$\frac{d_{1}}{d_{2}} = 2^{1 / 3}$

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A short bar magnet produces magnetic fields of equal induction at two points one on the axial line and the other on the equatorial line. The ratio of their distances is

The correct option is A 21/3:1Boxial=2μ0m4πd31B(ew)=μ0m4πd32Baxial=Beq2μ0n4πd31=μ0m4πd32(d1d2)3=2d1d2=21/3

The correct option is A 2 $^{1 / 3}$ :1
$B o x i a l = \frac{2 μ_{0} m}{4 π d_{1}^{3}}$
$B (e w) = \frac{μ_{0} m}{4 π d_{2}^{3}}$
$B a x i a l = B e q$
$\frac{2 μ_{0} n}{4 π d_{1}^{3}} = \frac{μ_{0} m}{4 π d_{2}^{3}}$
$(\frac{d_{1}}{d_{2}})^{3} = 2$
$\frac{d_{1}}{d_{2}} = 2^{1 / 3}$