A short bar magnet with its north pole facing north forms a neutral point at P in the horizontal plane. If the magnet is rotated by 90∘ in the horizontal plane, the net magnetic induction at P is (Horizontal component of earth’s magnetic field = )
A
0
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B
2BH
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C
√52BH
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D
√5BH
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Solution
The correct option is D√5BH Initially Neutral point obtained on equatorial line and at neutral point where BH = Horizontal component of earth’s magnetic field, Be = Magnetic field due to bar magnet on it’s equatorial line Finally Point P comes on axial line of the magnet and at P, net magnetic field B=√B2a+B2H =√(2Be)2+(BH)2=√(2BHH)2+B2H=√5BH