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Question

A short-circuited coil is placed in a time-varying magnetic field. Electrical power is dissipated due to the current induced in the coil. If the number of turns was to be quadrupled and the wire radius halved, the electric power dissipated would be

A
Halved
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B
The same
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C
Doubled
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D
Quadrupled
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Solution

The correct option is B The same
Power dissipated, P=e2R

where,

e= Induced emf =(dϕdt)

and

ϕ=NBA

Therefore,

e=NA(dBdt)

Also,

R1a1r2

Therefore,

P=e2RN2A2r2lN2r4l

As r is halved, then N is quadruples.

Therefore, P remains the same.


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