A short length of DNA contains 320 thymine and 320 guanine bases, then how many total N-bases will be present in this DNA?

640

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1280

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160

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Solution

The correct option is B 1280
According to Chargaff rule, there will be complementarity between adenine-thymine bases and cytosine-guanine bases in DNA. So, the number of bases in both these cases will be independent of the other set but will be dependent on the equivalent number of bases from the same set. So, when the DNA has 320 thymine and 320 guanine bases, it means that there will be an additional 320 adenine and 320 cytosine bases in the DNA. Thus the total number of base pairs will be 320*4=1280 bp.

So the correct option is '1280'.

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