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Question

A short magnet makes 40 oscillations per minute when used in an oscillations magnetometer at a place where the earth's horizontal magnetic field is 25 μ T. Another short magnet of magnetic moment 1.6 A m2 is placed 20 cm east of the oscillation if the magnet has its north pole (a) towards north and (b) towards south.


Solution

Here, γ1 = 40 oscillations/minute,

BH=25μ T

M of second magnet 

= 1.6 A-m2

d= 20 cm = 0.2 m

(a) For north pole facing 

γ1=12πMBH1

γ2=12πM(BHB)1

B= μ04πmd3

=107×1.68×103=20μ T

γ1γ2=BHBHB

40γ2=255

40γ2=5

γ2=405 = 17.88

= 18 osci/m.

(b) For north pole facing south 

γ1=12πMBH1

γ1=12πM(B+BH)1

γ1γ2=BHB+BH

40γ2=2545

γ2=402545 = 54 osci/m. 

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