A short magnet produces a deflection of 30o when placed at some distance in tanA position of the magnetometer. If another magnet of same length and double the pole strength is kept at the same distance in tanB position, the deflection produced is
A
30o
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B
60o
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C
45o
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D
0o
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Solution
The correct option is A30o Given, μ04π2Mdd3=BHtanθA μ04π2×Mdd3=BHtanθB From the above two equations, tanθA=tanθB ⇒θB=30∘ since given θA=30∘