A shower of rain appears to fall vertically downwards with a velocity 4km/h on a person walking westwards with a velocity of 3km/h. The actual velocity and direction of the rain is
A
1km/h clockwise to vertical
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B
5km/h, anticlockwise to vertical
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C
5km/h, clockwise to vertical
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D
1km/h, vertically downwards
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Solution
The correct option is C5km/h, clockwise to vertical VRain,Person=VRain−VPerson=−4^j (vertically down) Thus, VRain−(−3^i)=−4^j or, VRain=3^i−4^j Thus, magnitude = 5km/h, direction is in 4th quadrant, i.e. clockwise to vertical.