A shunt resistance 20 ohm is connected across a galvanometer in parallel, and the combination is connected to a cell of emf E through a resistance of 40 ohm. the ratio of potential difference across the shunt to that of the resistor is 1:3. what is the resistance of the galvanometer?

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Solution

Dear Student

$R e s i s \tan c e o f t h e g a l v a n o m e t e r G = \frac{R . S}{R - S} = \frac{40 \times 20}{40 - 20} G = \frac{800}{20} = 40 o h m$

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A shunt resistance 20 ohm is connected across a galvanometer in parallel, and the combination is connected to a cell of emf E through a resistance of 40 ohm. the ratio of potential difference across the shunt to that of the resistor is 1:3. what is the resistance of the galvanometer?

Dear Student Resistance of the galvanometerG=R.SR-S=40×2040-20G=80020=40 ohm Regards

Dear Student

$R e s i s \tan c e o f t h e g a l v a n o m e t e r G = \frac{R . S}{R - S} = \frac{40 \times 20}{40 - 20} G = \frac{800}{20} = 40 o h m$

Regards