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Darcy's Law

A silty-clay ...

Question

A silty-clay deposit 4 m thick lies between two layers of sand as shown below. If the coefficient of permeability of clay is $1 \times 10^{- 6} c m / s e c$ then the seepage through the clay is

A

4 \times 10^{- 8} m^{3} / s e c / m^{2}

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B

1.4 \times 10^{- 8} m^{3} / s e c / m^{2}

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C

0.67 \times 10^{- 8} m^{3} / s e c / m^{2}

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D

1.5 \times 10^{- 8} m^{3} / s e c / m^{2}

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Solution

The correct option is D $1.5 \times 10^{- 8} m^{3} / s e c / m^{2}$
Head causing the flow = 6 m
$Q = k . i . A = 1 \times 10^{- 6} \times 10^{- 2} \times \frac{6}{4} \times 1 m^{3} / s e c / m^{2}$
$= 1.5 \times 10^{- 8} m^{3} / s e c / m^{2}$

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