A silver and a zinc volameter are connected in series and a current I is passed through them for a time t, liberating W grams of zinc, Then weight of silver deposited is nearly

1.7 W gram

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2.4 W gram

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3.5 W gram

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1.2 W gram

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Solution

The correct option is C 3.5 W gram
According to Faraday's 2nd law of electrolysis, the amount of substance deposited at respective cathode is directly proportional to chemical equivalent.i.e $m \propto E$
Thus, $\frac{m_{A g}}{m_{Z n}} = \frac{E_{A g}}{E_{Z n}} = \frac{108}{31} = 3.5$
$m_{A g} = 3.5 \times m_{Z n} = 3.5 W$ gram

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A silver and a zinc volameter are connected in series and a current I is passed through them for a time t, liberating W grams of zinc, Then weight of silver deposited is nearly

The correct option is C 3.5 W gramAccording to Faraday's 2nd law of electrolysis, the amount of substance deposited at respective cathode is directly proportional to chemical equivalent.i.e m∝EThus, mAgmZn=EAgEZn=10831=3.5mAg=3.5×mZn=3.5W gram