You visited us 2 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Chemistry

Electrolysis and Electrolytes

A silver elec...

Question

A silver electrode is immersed in saturated $A g_{2} S O_{4} (a q)$ . The potential difference between the silver and the standard hydrogen electrode is found to be 0.711 V. If the $K_{s p} (A g_{2} S O_{4})$ is $x \times 10^{- 3}$ .

[Given, $E_{A g^{+} / A g}^{o} = 0.799 V$ ]

The value of $100 x$ is:

164

No worries! We‘ve got your back. Try BYJU‘S free classes today!

134

No worries! We‘ve got your back. Try BYJU‘S free classes today!

106

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D 106
The expression for the emf of the cell is
$E_{c e l l} = E_{c e l l}^{0} - \frac{0.0592}{n} l o g \frac{1}{K_{s p}}$
Substitute values in the above expression
$0.711 = 0.799 - \frac{0.0592}{2} l o g \frac{1}{K_{s p}}$
$l o g \frac{1}{K_{s p}} = 2.9729$
$\frac{1}{K_{s p}} = 939.66$
$K_{s p} = 1.06 \times 10^{- 3}$
$x = 1.06$
$100 x = 106$

Suggest Corrections

Similar questions

Q. A silver electrode is immersed in saturated

A g_{2} S O_{4 (a q)}

. The potential difference between silver and the standard hydrogen electrode is found to be

0.711

V. Determine

K_{s p}

(A g_{2} S O_{4})

[Given

E_{A g^{+} / A g}^{0} = 0.799 V

]

Q. A silver electrode is immersed in saturated

A g_{2} S O_{4} (a q .)

. The potential difference between silver and the standard hydrogen electrode is found to be

0.711 V

. Determine

K_{s p} (A g_{2} S O_{4})

. (Given,

E_{A g^{+} / A g}^{\circ} = 0.799 V)

Q. A silver electrode is immersed in saturated

A g_{2} S O_{4} (a q)

. The potential difference between silver and the standard hydrogen electrode is found to be

0.711 V

.
Determine the

K_{s p}

A g_{2} S O_{4}

25^{o} C

.
Given:

E_{A g^{+} / A g}^{0} = 0.799 V 10^{- 1.5} \approx 0.031

Q. A sample of lead weighing

1.05 g

was dissolved in a small quantity of nitric acid to produce an aqueous solution of

{P b}^{2 +}

and

{A g}^{+}

(which is present as impurity). The volume of the solution was increased to

300 m l

by adding water, a pure silver electrode was immersed in the solution and the potential difference between this electrode and a standard hydrogen electrode was found to be

0.503 V

25^{o} C

. What was the % of

A g

in the lead metal? (Given :

E_{({A g}^{+} / A g)}^{o} = 0.799 V

. Neglect amount of

{A g}^{+}

converted to

A g

)

Q. A silver wire dipped in

0.1 M H C l

solution saturated with

A g C l

develops oxidation potential of

- 0.208 V

.
The standard electrode potential of

E_{A g^{+} / A g}^{\circ} = - 0.799 V

, then

K_{s p}

A g C l

in pure water will be

Join BYJU'S Learning Program

A silver electrode is immersed in saturated Ag2SO4(aq). The potential difference between the silver and the standard hydrogen electrode is found to be 0.711 V. If the Ksp(Ag2SO4) is x×10−3.[Given, EoAg+/Ag=0.799V]The value of 100x is:

The correct option is D 106The expression for the emf of the cell is Ecell=E0cell−0.0592nlog1KspSubstitute values in the above expression0.711=0.799−0.05922log1Ksplog1Ksp=2.97291Ksp=939.66Ksp=1.06×10−3x=1.06100x=106