A silver ingot weighing $2.1$ kg is held by a string so as to be completely immersed in a liquid of relative density $0.8$ . The relative density of silver is $10.5$ . The tension in the string and the buoyant force is _____.

Buoyant force is 1.5 N

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Tension is 19.4 N

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Buoyant force is 3.1 N

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Tension is 12.5 N

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Solution

The correct option is A Tension is 19.4 N

$vol. of silver = \frac{2.1}{10.5} = \frac{1}{5}$

$Tension = m g - Bovency.$

$= 21 - \frac{0.8 \times 10}{5}$

$= 19.4 N$

$Answer:- (B)$

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A silver ingot weighing 2.1kg is held by a string so as to be completely immersed in a liquid of relative density 0.8. The relative density of silver is 10.5. The tension in the string and the buoyant force is _____.

The correct option is A Tension is 19.4 N vol. of silver =2.110.5=15 Tension =mg− Bovency. =21−0.8×105=19.4 N Answer:- (B)

A silver ingot weighing $2.1$ kg is held by a string so as to be completely immersed in a liquid of relative density $0.8$ . The relative density of silver is $10.5$ . The tension in the string and the buoyant force is _____.

The correct option is A Tension is 19.4 N

$vol. of silver = \frac{2.1}{10.5} = \frac{1}{5}$

$Tension = m g - Bovency.$

$= 21 - \frac{0.8 \times 10}{5}$

$= 19.4 N$

$Answer:- (B)$