A silver ornament is suspected to be hollow. Its weight is 250g and it displaces 50 cc of water. If the relative density of silver be 10, find the volume of the cavity.

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Solution

Density of silver = $10 g / c m^{3}$
Mass of silver in the ornament
=250 g {As air has negligible density}
$∴$ volume of silver = $\frac{m}{d} = \frac{250}{10} = 25 c m^{3}$
$∴$ Volume of cavity $= 50 c m^{3} - 25 c m^{3}$
$= 25 c m^{3}$

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A silver ornament is suspected to be hollow. Its weight is 250g and it displaces 50 cc of water. If the relative density of silver be 10, find the volume of the cavity.

Density of silver =10g/cm3 Mass of silver in the ornament =250 g {As air has negligible density} ∴ volume of silver =md=25010=25cm3 ∴ Volume of cavity =50cm3−25cm3 =25cm3

Density of silver = $10 g / c m^{3}$
Mass of silver in the ornament
=250 g {As air has negligible density}
$∴$ volume of silver = $\frac{m}{d} = \frac{250}{10} = 25 c m^{3}$
$∴$ Volume of cavity $= 50 c m^{3} - 25 c m^{3}$
$= 25 c m^{3}$