Question

A simple harmoinic motion is represented by $F\left(t\right)=10\sin (10\tau +0.5)$. The amplitude of the S.H.M. is

• A. $a=30$
• B. $a=20$
• C. $a=10$
• D. $a=5$

Answer 1

The correct option is C $a=10$

We know that SHM is represented by

$F(x,t)=Asin(wt-kx)$

Here,

$A=amplitute$

$w=frequency$

Given,

$F\left(t\right)=10sin(10t+0.5)$

By comparing both the equation we get

$A=10$

Correct option is C.