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Question

A simple harmonic motion has an amplitude A & time period T. The time required by it to travel from x=A to x=A2 is

A
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B
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C
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D
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Solution

The correct option is A
Time required to travel from x = A to x = 0 is T4 & time required to travel from x=A2 to x=0 is equal to the time required to travel from x=0 to x=A2 which is obtained from
y=Asin(2πT)tA2=Asin(2πT)tsin(π6)=sin(2πT)tt=T12Time required to travel from x=A to x=A2 will beT4T12=T6(A)

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