A simple harmonic oscillation is represented by the equation y - 0-4 sin 440t-7-0-61x - Where -Y- and -X- are in m and time -t- in seconds respectively- The value of time period in seconds

The correct option is A 0.1It is given that, #10; #10; y=0.4sin( 4407t+0.61x ) #10; #10;From the above equation: #10; #10; ω =4407 #10; ...

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Standard XII

Physics

Phasors

A simple harm...

Question

A simple harmonic oscillation is represented by the equation y $= 0.4 s i n (\frac{440 t}{7} + 0.61 x)$ . Where 'Y' and 'X' are in m and time 't' in seconds respectively. The value of time period in seconds

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Solution

The correct option is A 0.1
It is given that,

$y = 0.4 sin (\frac{440}{7} t + 0.61 x)$

From the above equation:

$ω = \frac{440}{7}$

$\frac{2 π}{T} = \frac{440}{7}$

$\frac{2 \times 22}{7 T} = \frac{440}{7}$

$T = 0.1 s$

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A simple harmonic oscillation is represented by the equation y =0.4sin(440t7+0.61x). Where 'Y' and 'X' are in m and time 't' in seconds respectively. The value of time period in seconds

The correct option is A 0.1It is given that, y=0.4sin(4407t+0.61x) From the above equation: ω=4407 2πT=4407 2×227T=4407 T=0.1s

A simple harmonic oscillation is represented by the equation y $= 0.4 s i n (\frac{440 t}{7} + 0.61 x)$ . Where 'Y' and 'X' are in m and time 't' in seconds respectively. The value of time period in seconds

The correct option is A 0.1
It is given that,

$y = 0.4 sin (\frac{440}{7} t + 0.61 x)$

From the above equation:

$ω = \frac{440}{7}$

$\frac{2 π}{T} = \frac{440}{7}$

$\frac{2 \times 22}{7 T} = \frac{440}{7}$

$T = 0.1 s$