Question

A simple harmonic oscillator has a period T and energy E. The amplitude of the oscillator is doubles. Choose the correct answer.

• A. Period and energy get doubled.
• B. Period gets doubled while energy remains the same.
• C. Energy gets doubled while period remains the same.
• D. Period remains the same and energy becomes four times.

Answer 1

The correct option is D Period remains the same and energy becomes four times.

The period of harmonic oscillator does not depend on the amplitude of oscillation. Energy of oscillation.
Energy of oscillator, $E=\frac{1}{2}m{\omega }^2{A}^2,E\propto A^2$
So, if amplitude (A) is doubled, its energy becomes $4$ times.