The correct option is
D sint−12sin2tAccording to the question,
Given; F=Fsint⇒a=Fmsint⇒v=−Fmcost
x=−Fmsint⇒X=r→x1+r→x2=Asin2t−Fmsint..............................eq−i
Now, we know that in SHM,
a (acceleration)=−ω2Asinωt and above we find a=Fmsint
Resultant force, Fresultant=sint−mω2Asinwt
⇒FR=sint−4mAsin2t (Given, ω=2radian/s)
⇒aR=sint/m−4Asin2t (By integrating)
⇒vR=−cost/m+2Acos2t (By integrating)
⇒xR=−sint/m+Asin2t
We can write, xR=−1m(sint−Amsin2t) ⇒xR∝(sint−Amsin2t)
Only option D is in the given form, Hence, option D is correct.