wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A simple microscope is rated 5 X for a normal relaxed eye. What will be its magnifying power for a relaxed farsighted eye whose near point is 40 cm?

A
5
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
12.5
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
200
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
8
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D 8
The near point is closest distance at which the eye lens can form a clear image of the object.



When an object is closer than the near point, image formed is blurry. In that case, a magnifier lens is used. The object will be at the magnifier's focal length and the magnifier will converge the light rays, so that the rays reaching the eye lens are parallel.


Magnification of a simple microscope (magnifier)
m=Df

For a normal eye,
m=5 (given)
D=25 cm (near point of a normal eye)
f=255=5 cm
(focal length of magnifier lens)

For the hypermetropic eye,
D=40 cm (given)
Hence m=Df=405=8

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Simple Microscope
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon