A simple microscope is rated 5x for a normal relaxed eye. What will be its magnify power for a far sighted man whose near point is 40 cm?

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Solution

The correct option is D 8x
Magnification of a simple microscope is given as
$M = \frac{D}{f}$
where D is the least distance of distinct image for the person
and f is the focal length of the lens used.
$⟹ 5 = \frac{25}{f}$
$⟹ f = 5 c m$
Hence for the far sighted man, $M^{'} = \frac{D^{'}}{f} = \frac{40}{5} = 8$

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A simple microscope is rated 5x for a normal relaxed eye. What will be its magnify power for a far sighted man whose near point is 40 cm?

The correct option is D 8xMagnification of a simple microscope is given as M=Dfwhere D is the least distance of distinct image for the personand f is the focal length of the lens used.⟹5=25f⟹f=5cmHence for the far sighted man, M′=D′f=405=8