A simple pendulum 1 metre long has a bob of 10 kg. lf the pendulum swings from a horizontal position, the kinetic energy of the bob, at the instant it passes through the lowest position of its path is: (Take $g = 9.8 / m / s^{2}$ )

89 joule

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95 joule

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98 joule

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85 joule

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Solution

The correct option is C 98 joule
As the pendulum falls from horizontal position to its lowest point, displacement of the bob is equal to $l$
From
$v^{2} - u^{2} = 2 a s$
$v^{2} = 2 g l$
Kinetic energy at the lower point $= \frac{1}{2} m v^{2} = 0.5 (10) (2) (9.81) (1) = 98.1 J$
Option C.

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A simple pendulum 1 metre long has a bob of 10 kg. lf the pendulum swings from a horizontal position, the kinetic energy of the bob, at the instant it passes through the lowest position of its path is: (Take g=9.8/m/s2)

The correct option is C 98 jouleAs the pendulum falls from horizontal position to its lowest point, displacement of the bob is equal to lFromv2−u2=2asv2=2glKinetic energy at the lower point=12mv2=0.5(10)(2)(9.81)(1)=98.1JOption C.

A simple pendulum 1 metre long has a bob of 10 kg. lf the pendulum swings from a horizontal position, the kinetic energy of the bob, at the instant it passes through the lowest position of its path is: (Take $g = 9.8 / m / s^{2}$ )

The correct option is C 98 joule
As the pendulum falls from horizontal position to its lowest point, displacement of the bob is equal to $l$
From
$v^{2} - u^{2} = 2 a s$
$v^{2} = 2 g l$
Kinetic energy at the lower point $= \frac{1}{2} m v^{2} = 0.5 (10) (2) (9.81) (1) = 98.1 J$
Option C.