A simple pendulum executing $S H M$ with a period of $6 s$ between two extreme positions $B$ and $C$ about a point $O$ . If the length of the arc $B C$ is $10$ cm, how long will the pendulum take the move from position $C$ to a position $D$ towards $O$ exactly midway between $C$ and $O$ ?

0.5 s

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1 s

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1.5 s

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

3 s

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $1.5 s$
O is the mean position and B and C are extreme positions.
Given: BC = $10$ cm
Since B and C are the extreme positions, therefore amplitude of the SHM oscillation is 5cm
Now time taken for covering 10cm =6s
so time for $10 / 4$ cm = $\frac{6 * 2.5}{10}$
=1.5s
D is the midway between C and O.

Suggest Corrections

Similar questions

Q. A simple pendulum is moving simple harmonically with a period of 6 s between two extreme position B and C about a point O. If the angular distance between B and C is 10 cm, how long will the pendulum take to move from position C to a position D exactly midway between O and C

Q. A simple pendulum is oscillating between extreme positions

P

and

Q

about the mean position

O

. Which of the the following statements are true about the motion of pendulum?

Q. In the figure given below, an ideal pendulum oscillates in vacuum between two extreme positions

A

and

B

. If it goes from position

A

to position

B

and then returns from position

B

to mean position

C

3 s

, then it will complete

3.5

oscillations in

Name the type of energy possessed by the bob of a simple pendulum when it is at (a) the extreme position,(b) the mean position, and (c) between the mean and extreme positions.

Join BYJU'S Learning Program

A simple pendulum executing SHM with a period of 6s between two extreme positions B and C about a point O. If the length of the arc BC is 10cm, how long will the pendulum take the move from position C to a position D towards O exactly midway between C and O?

The correct option is B 1.5sO is the mean position and B and C are extreme positions.Given: BC = 10cmSince B and C are the extreme positions, therefore amplitude of the SHM oscillation is 5cmNow time taken for covering 10cm =6sso time for 10/4cm =6∗2.510 =1.5sD is the midway between C and O.

A simple pendulum executing $S H M$ with a period of $6 s$ between two extreme positions $B$ and $C$ about a point $O$ . If the length of the arc $B C$ is $10$ cm, how long will the pendulum take the move from position $C$ to a position $D$ towards $O$ exactly midway between $C$ and $O$ ?