wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A simple pendulum fixed in a car has a time period of 4 seconds when the car is moving uniformly on a horizontal road. When the accelerator is pressed, the time period changes to 3.99 seconds. Making an approximate analysis, find the acceleration of the car.

Open in App
Solution

It is given that:
When the car is moving uniformly, time period of simple pendulum, T = 4.0 s
As the accelerator is pressed, new time period of the pendulum, T' = 3.99 s
Time period of simple pendulum, when the car is moving uniformly on a horizontal road is given by,
T=2πlg4=2πlg
Let the acceleration of the car be a.
The time period of pendulum, when the car is accelerated, is given by:
T'=2πlg2+a2123.99=2πlg2+a212Taking the ratio of T to T', we get:TT'=43.99=g2+a21/4g
On solving the above equation for a, we get:
a=g10 ms-2

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Equations of Motion tackle new
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon