A simple pendulum hanging from the ceiling of a stationary lift has a time period $T_{1}$ . When the lift moves downward with constant velocity, the time period is $T_{2}$ , then

T₂ is infinity

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T₂> T₁

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T₂< T₁

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T₂ = T₁

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Solution

The correct option is D
T₂ = T₁

As the lift moves down with constant velocity, the effective acceleration due to gravity remains the same i.e., g so the time period remains the same!

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A simple pendulum hanging from the ceiling of a stationary lift has a time period T1. When the lift moves downward with constant velocity, the time period is T2, then

The correct option is D T2 = T1 As the lift moves down with constant velocity, the effective acceleration due to gravity remains the same i.e., g so the time period remains the same!

A simple pendulum hanging from the ceiling of a stationary lift has a time period $T_{1}$ . When the lift moves downward with constant velocity, the time period is $T_{2}$ , then

The correct option is D
T₂ = T₁

As the lift moves down with constant velocity, the effective acceleration due to gravity remains the same i.e., g so the time period remains the same!