A simple pendulum hanging from the ceiling of a stationary lift has time period $t_{1}$ . When the lift moves downward with constant velocity, the time period is $t_{2}$ , then

t_{2}

is infinity

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t_{2} > t_{1}

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t_{2} < t_{1}

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t_{2} = t_{1}

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Solution

The correct option is D $t_{2} = t_{1}$
The lift is moving with constant velocity so, there will be no change in the acceleration hence time period will remain same.

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