A simple pendulum has a length of $4 m$ and acceleration due to gravity is taken to be $9.8 {m/s}^{2}$ . What is the approximate value of the time period?

2 s

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4 s

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3 s

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1 s

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Solution

The correct option is B $4 s$
Time period $= 2 π \sqrt{\frac{l}{g}}$
Time period $= 2 (3.14) \sqrt{\frac{4}{9.8}}$
Time period $≃ 4 s$

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A simple pendulum has a length of 4 m and acceleration due to gravity is taken to be 9.8 m/s2. What is the approximate value of the time period?

The correct option is B 4 sTime period =2π√lg Time period =2(3.14)√49.8 Time period ≃4 s

A simple pendulum has a length of $4 m$ and acceleration due to gravity is taken to be $9.8 {m/s}^{2}$ . What is the approximate value of the time period?

The correct option is B $4 s$
Time period $= 2 π \sqrt{\frac{l}{g}}$
Time period $= 2 (3.14) \sqrt{\frac{4}{9.8}}$
Time period $≃ 4 s$