A simple pendulum has a time period of 3.0 s. If the point of suspension of the pendulum starts moving vertically upward with a velocity v = kt where k=4.4ms−2, the new time period will be (Take g = 10 ms−2
2.5 s
Given, v=4.4t⇒a=4.4 m/s2
When the point of suspension starts moving upward, effective acceleration, g′=g+a=14.4 m/s2
Now, T′T=2π√lg′2π√lg=gg′=1014.4⇒T′=1012×3=2.5 s