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Question

A simple pendulum has time period T1. The point of suspension is now moved upward according to the relation y = kt2, (k =1ms2) where y is the vertical displacement. The time period now becomes T2. The ratio of T21T22 is (Take g = 10 ms2)


A

65

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B

56

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C

1

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D

45

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Solution

The correct option is A

65


Point of suspension is moving as

y=kt2(k=1ms2)

y=t2

dydt=2t

d2ydt2=2

So accleration of suspension point =2ms2

So from non-intertial frame the bob will feelg and a (pseudo scceleration) downward

T=2πlg

geffective will be (g+a)=10+2=12ms2

T2=2πlgeff

T21T22=1210=65


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