A simple pendulum is attached to the roof of a lift. Its time period of oscillation, when the lift is stationary is 0.5 s. Its frequency of oscillation when the lift falls freely will be
A
infinite
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B
zero
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C
2 Hz
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D
20 Hz
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Solution
The correct option is B zero When lift falls with acceleration g, net effective force acting on pendulum is 0 (mg downwards due to gravity and mg upwards due to pseudo force.). Thus net acceleration will be zero. Now, frequency, f=1/T=1/2π√geff/l=0 (because geff=0)