Question

A simple pendulum is of length 50 cm .Find time period and frequency of oscillation (g=9.8m/s${}^2$)

• A. 1.38 sec, 0.7246Hz
• B. 2.419 ec, 0.5.45 Hz
• C. 5.619 sec, 0.6045 Hz
• D. 1.419, 0.7045 Hz

Answer 1

The correct option is A 1.38 sec, 0.7246Hz

Length of pendulum, $l=50cm=0.5m$

Time period of pendulum is,

$T=2\pi \sqrt{\frac{l}{g}}$

$T=2\pi \sqrt{\frac{0.5}{10}}$

$T=1.38s$

Frequency,

$\nu =\frac{1}{T}=\frac{1}{1.38}=0.72Hz$