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Question

A simple pendulum is of length 50cm. Find its time period and frequency of oscillation.(g 9.8m/s2 )

A
2.419 sec, 0.8045Hz
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B
3.219 sec, 0.5045Hz
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C
5.619 sec, 0.6045Hz
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D
1.419 sec, 0.7045Hz
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Solution

The correct option is D 1.419 sec, 0.7045Hz
Length of pendulum = 50 cm
50100m=12m
Given g=9.8m/s2
Time period of simple pendulum
T=2πg=2πY29.8=2π12×9.8sec=2π×0.22sec=2×3.14×0.22=1.419secFrequencyn=1T=11.419=0.7045Hz
Option D.

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