A simple pendulum is set up in a trolley which moves to the right with an acceleration a on a horizontal plane. Then the thread of the pendulum in the mean position makes an angle θ with the vertical

$tan^{-1} \left( \frac ag \right)$ in the forward direction

No worries! We‘ve got your back. Try BYJU‘S free classes today!

$tan^{-1} \left( \frac ag \right)$ in the backward direction

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

$tan^{-1} \left( \frac {g}{a} \right)$ in the backward direction

No worries! We‘ve got your back. Try BYJU‘S free classes today!

$tan^{-1} \left( \frac {g}{a} \right)$ in the forward direction

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B
$tan^{-1} \left( \frac ag \right)$ in the backward direction

In accelerated frame of reference, a fictitious force (pseudo force)

ma acts on the bob of pendulum as shown in figure.

Hence, tan $θ$ = $\frac{m a}{m g} = \frac{a}{g}$

$\Rightarrow θ = t a n^{- 1} (\frac{a}{g})$ in the backward direction.
•

Suggest Corrections

Similar questions

Q. A simple pendulum is setup in a trolly which moves to the right with an acceleration

a

on a horizontal plane. Then, the thread of the pendulum in the mean position makes an angle with the vertical is

Q. A simple pendulum is suspended from the roof of a trolley which moves in a horizontal direction with an acceleration

a,

then the time period is given by

r = 2 π \sqrt{\frac{l}{g^{'}}}

where

g^{'}

is equal to

Q. A simple pendulum is suspended from the roof of a trolley which moves, in a horizontal direction with an acceleration

a

, and its time period is given by

T = 2 π \sqrt{\frac{l}{g^{'}}}

which of the following correctly represent the value of

g^{'}

In the following figure, find the direction of friction on the blocks $A$ and $B$ and the ground respectively.

A simple pendulum is suspended from the roof of a trolley which moves in a horizontal direction with an acceleration a, then the time period is given by $T = 2 π \sqrt{\frac{l}{g^{'}}}$ , where g' is equal to

Join BYJU'S Learning Program

A simple pendulum is set up in a trolley which moves to the right with an acceleration a on a horizontal plane. Then the thread of the pendulum in the mean position makes an angle θ with the vertical

The correct option is B in the backward direction In accelerated frame of reference, a fictitious force (pseudo force) ma acts on the bob of pendulum as shown in figure. Hence, tan θ = mamg=ag ⇒θ=tan−1(ag) in the backward direction. •