Question

A simple pendulum is taken from the equator to the pole. Its period

• A. Decreases
• B. Increases
• C. Remains the same
• D. Decreases and then increases

Answer 1

The correct option is A Decreases

As we go from equator to pole the value of $g$ increase.

Therefore time period of simple pendulum $(T\propto \frac{1}{\sqrt{g}})$ decrease $(\because T\propto \frac{1}{\sqrt{g}})$