Question

A simple pendulum of 1 metre length oscillates in a vertical plane. The minimum time required by ball to move from a position of maximum speed to a state of maximum acceleration is (take $\sqrt{g}=\pi )$

• A. 2 $s$
• B. 1 $s$
• C. 0.5 $s$
• D. 3 $s$

Answer 1

The correct option is B 1 $s$

Maximum speed is at mean position and maximum acceleration is at extreme position. Therefore, minimum time required by particle is $\frac{T}{4}=\frac{2\pi }{2}\times \sqrt{\frac{l}{g}}=1s$