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Question

A simple pendulum of bob of mass m and length l has one of its ends fixed at the centre O of a vertical circle, as shown in the figure. If θ=60 at the point P, the minimum speed u that should be given to the bob so that it completes a vertical circle is

A
gl
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B
2gl
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C
5gl2
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D
3gl2
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Solution

The correct option is B 2gl

At point B,
TB+mg=mv2Bl
For particle to complete vertical circle,
TB0
mv2BLmg
v2BgL --- (1)

Applying conservation of energy principle,
12mv2A=mgl(1cosθ)+12mv2B
12mv2A=mgl(112)+12mgl
vA=2gl is the minimum speed that must be given to the bob.

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