A simple pendulum of length $1$ m has a bob of mass $100$ g. It is displaced through an angle of $60^{o}$ from the vertical and then released . Find out K.E. of bob when it passes through mean position.

0.12

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0.24

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0.36

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0.55

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Solution

The correct option is D $0.55$ J
Length of simple pendulum $= 1 m$
Mass $= 1 w g m = 0.1 k g$
It is displaced through as angle of $60$ for vertical
Height of pendulum at starting position $=$ length $(1 - w s 60)$
$= 1 (1 - 0.5)$
$= 0.5 m$
Potential energy $= m g h = 0.1 \times 10 \times 0.5 = 0.55$
when it is released and it reaches mean position its potential energy at starting point is converted to kinetic energy.
so K.E. of bob at mean position $= 0.55.$
Hence, the answer is $0.55.$

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Q. A simple pendulum of length 1 m has a bob of mass 200 g. It is displaced

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