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Question

A simple pendulum of length 1 m is taken to height h (h = R = radius of the earth) from the earth’s surface.
The time period of small oscillation of the pendulum at that point is (g=π2ms2)

A
2 s
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B
3 s
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C
4 s
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D
1 s
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Solution

The correct option is C 4 s
At height h, g/=GM(R+h)2=GM(R+R)2=g4
T=2πlg/=2π114×π2=2π(2π)=4s

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