A simple pendulum of length 20 cm and of mass 0-1 kg is pulled to one side through an angle - and released- if its maximum velocity is 1-4 ms-1- the value of - - is-

The correct option is A 30From above figure #160;applying energy conservation from A to B 12 mv_A^2 + mg l (1 cos θ) = 12 mv_B^2 + mg(0) Given #160; ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Physics

Physical Pendulum

A simple pend...

Question

A simple pendulum of length 20 cm and of mass 0.1 kg is pulled to one side through an angle $^{'} θ$ ' and released. if its maximum velocity is $1.4 m s^{- 1}$ , the value of ' $θ^{'}$ is.

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A 30
From above figure
applying energy conservation from A to B
$\frac{1}{2} m v_{A}^{2} + m g l (1 - c o s θ) = \frac{1}{2} m v_{B}^{2} + m g (0)$
Given
$v_{A} = 0$
l = 0.2m
m = 1kg
$g (0.2) (1 - c o s θ) = \frac{1}{2} (1.4) (1.4)$
$c o s θ = 0.5$
$c o s θ = \frac{1}{2}$
so
$θ = 30^{\circ}$
Hence (A) is correct answer

Suggest Corrections

Similar questions

Q. The bob of a pendulum of length l is pulled a side from its equilibrium position through an angle

θ

and then released. The bob will; then pass through its equilibrium position with a speed

ν

, where

ν

equals to :

Q. A suspended simple pendulum of length

l

is making an angle

θ

with the vertical. On releasing, its velocity at lowest point will be:-

Q. A suspended simple pendulum of length

l

is making an angle

θ

with the vertical. On releasing, its velocity at lowers point will be

Q. The figure shows a pendulum of length

^{'} I^{'}

suspended at a distance

x

vertically above a peg. The pendulum bob is deflected through an angle

θ

and then released. When

θ = 90^{\circ}

, the pendulum complete the circle. When

θ = 60^{\circ}

the velocity of the bob as it passes position

E

\sqrt{k l}

. Find the value of

k (g = 10 m / s e c^{2})

Q. The bob of a simple pendulum of length

50

cm is pulled to one side such that it makes an angle of

30^{o}

with a verticle and released. If the mass of the bob is

200

g, the kinetic energy at the mean position is ____ J.

T a k e g = {10 m s}^{- 2}

Join BYJU'S Learning Program

A simple pendulum of length 20 cm and of mass 0.1 kg is pulled to one side through an angle ′θ' and released. if its maximum velocity is 1.4ms−1, the value of 'θ′ is.

The correct option is A 30From above figure applying energy conservation from A to B12mv2A+mgl(1−cosθ)=12mv2B+mg(0)Given vA=0 l = 0.2m m = 1kgg(0.2)(1−cosθ)=12(1.4)(1.4)cosθ=0.5cosθ=12soθ=30∘Hence (A) is correct answer

A simple pendulum of length 20 cm and of mass 0.1 kg is pulled to one side through an angle $^{'} θ$ ' and released. if its maximum velocity is $1.4 m s^{- 1}$ , the value of ' $θ^{'}$ is.