Question

A simple pendulum of length $40cm$ oscillates with an angular amplitude of $0.04rad$. Find the time period of the oscillations.

• A. $1.26s$
• B. $1.58s$
• C. $2.52s$
• D. $2.58s$

Answer 1

The correct option is A $1.26s$

The angular frequency is $\omega =\sqrt{\frac{g}{l}}=\sqrt{\frac{10m/s^2}{0.4m}}=5s^{-1}$

The time period is $\frac{2\pi }{\omega }=\frac{2\pi }{5s^{-1}}=1.26s$