Question

A simple pendulum of length L and mass (bob) M is oscillating in a plane about a vertical line between angular limit - $\varphi$ and + $\varphi$. For an angular displacement $\theta (|\theta |<\varphi )$, the tension in the string and the velocity of the bob are T and V, respectively. The following relations hold good under the above conditions:

• A. $T\cos \theta =Mg$
• B. $T-Mg\cos \theta =\frac{M{V}^2}{L}$
• C. The magnitude of the tangential acceleration of the bob $a_T=g\sin \theta$
• D. $T=Mg\cos \theta$.

Answer 1

Answer: (B), (C)

The correct options are
B $T-Mg\cos \theta =\frac{M{V}^2}{L}$
C The magnitude of the tangential acceleration of the bob $a_T=g\sin \theta$

B. $T-Mg\cos \theta =\frac{M{V}^2}{L}$

C. The magnitude of the tangential acceleration of the bob $a_T=g\sin \theta$

Hence, the answers are both.