A simple pendulum of length l is suspended from the ceiling of a train which is moving in the horizontal direction with a constant acceleration a. The time period of the pendulum is given by T=2π√lgeff where geff is given by
A
g
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B
(g+a)
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C
(g- a)
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D
√g2+a2
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Solution
The correct option is D√g2+a2 There are two perpendicular acceleration vectors; g acting vertically downwards and a acting horizontally. The resultant acceleration is given by geff=√g2+a2
Hence the correct choice is (d)