A simple pendulum starts oscillating from the mean position A. If it moves towards extreme position B and then comes to extreme position C via A in $3$ s, the time period of the pendulum is

6 s

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3 s

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2 s

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4 s

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Solution

The correct option is D $4 s$
One complete oscillation will be when it comes back to $A =$ Time period

Time taken to cover $\frac{3}{4} t h$ oscillation $= 3 s$

Time period $= \frac{3}{3} \times 4 = 4 s$

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A simple pendulum starts oscillating from the mean position A. If it moves towards extreme position B and then comes to extreme position C via A in 3 s, the time period of the pendulum is

The correct option is D 4 s One complete oscillation will be when it comes back to A= Time period Time taken to cover 34th oscillation =3 s Time period =33×4=4 s

A simple pendulum starts oscillating from the mean position A. If it moves towards extreme position B and then comes to extreme position C via A in $3$ s, the time period of the pendulum is

The correct option is D $4 s$
One complete oscillation will be when it comes back to $A =$ Time period

Time taken to cover $\frac{3}{4} t h$ oscillation $= 3 s$

Time period $= \frac{3}{3} \times 4 = 4 s$