Question

A simple pendulum with a bob of mass 'm' swings with angular amplitude of 6060, the tension in the string would be:

• A. $3\sqrt{3}mg$
• B. $\frac{mg}{2}(3\sqrt{3}-2)$
• C. $\frac{mg}{3}(3\sqrt{3}-2)$
• D. $\frac{mg}{2}\left(3\sqrt{2}\right)$

Answer 1

The correct option is D $\frac{mg}{2}\left(3\sqrt{2}\right)$

$V_o=\sqrt{2g\frac{l}{2}(\sqrt{3}-1)}$

$T-mgcos{30}^0=\frac{m{v}^2}{l}.$

$T-\frac{\sqrt{3mg}}{2}=m\frac{gl}{l}(\sqrt{3}-1).$

$T=mg\left[\frac{3\sqrt{3-1}}{2}\right].$